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3x^2-51x+180=0
a = 3; b = -51; c = +180;
Δ = b2-4ac
Δ = -512-4·3·180
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-51)-21}{2*3}=\frac{30}{6} =5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-51)+21}{2*3}=\frac{72}{6} =12 $
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